0.872g sample containing only NaBr and KBr gives 1.052g AgBr. what's the % of each salt?
This is the type of problem that cannot be answered without other information.
I think you have made a typo in your problem I worked through it and I get negative numbers for the mass of NaBr and KBr. Of course that can not be. Perhaps the mass AgBr produced is 1.502 and not 1.052; that is, perhaps you transposed those numbers. Check it out.
The problem is set up this way but you will need to substitute the correct values. I have used 1.502g for mass AgBr produced.
You have two equations and two unknowns.
Let Y = grams KBr.
Let Z = grams NaBr.
Note: AgBr, KBr, and NaBr below stand for molar mass of those materials.
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eqn 1 is Y + Z = 0.872
eqn 2 is Y(AgBr/KBr) + Z(AgBr/NaBr)=1.502
Solve for Y and Z which is grams of each.
Then determine % by
%KBr = (massKBr/1.502)*100 and
%NaBr=(mass NaBr/1.502)*100.
Post your work if you get stuck.
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