0=(6(3x^2-2))/(x^2+2)^3 Solve for 0

Answer 1

You mean, solve for x
(6(3x^2-2))/(x^2+2)^3 = 0

(x^2+2)^3 cannot be zero, or else we would be dividing by zero, so
(6(3x^2-2)) = 0
3x^2- 2 = 0
x^2 = 2/3
x = ± √(2/3)

Answer 2

Thank you Reiny!