multiply the entire first line by (3/2)
0.3x(3/2) -0.2y(3/2)=4(3/2)
0.5x+0.3y=-7/17
and get
0.45x -0.3y =6
0.5x + 0.3y =-7/17
---------------------subtract
-0.05x = 6 7/17
-.05 x = 109/17
solve for x and go back and get y
0.3x-0.2y=4
0.5x+0.3y=-7/17
Can anyone Please help me solve using the elimination system.....
4 answers
See my above answer. Elimination as a process pretty much works the same no matter what, even if what you have to work with is a little ugly.
This is very confusing I do not get it
I multiplied the first equation, all terms by 3/2 to get o.3 in front of y in both equations
0.3x(3/2) -0.2y(3/2)=4(3/2)
0.5x+0.3y=-7/17
and get
0.45x -0.3y =6
0.5x + 0.3y =-7/17
---------------------add
.95 x = 95/17
0.3x(3/2) -0.2y(3/2)=4(3/2)
0.5x+0.3y=-7/17
and get
0.45x -0.3y =6
0.5x + 0.3y =-7/17
---------------------add
.95 x = 95/17