0.350 L of 0.470 M H2SO4 is mixed with 0.300 L of 0.250 M KOH. What concentration of sulfuric acid remains after neutralization?

Answer 1

Your question is poorly worded in my opinion. By my definitions, if the H2SO4 is neutralized then there will not be ANY H2SO4 left. What the problem means, I think, is after the addition of that much KOH to that much H2SO4, what is the concn of H2SO4.

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
mols H2SO4 = M x L = estimated 0.16
mols KOH added = M x L = estimated 0.075

So 0.075 mols KOH uses 1/2 x 0.075 mols H2SO4 or estimated 0.037. Then 0.16-0.o37 = approx 0.12 mols H2SO4 remaining.
(H2SO4) = mols/total L.

Answer 2

HUH