0.250 moles of HCL and 0.100 moles of acetic acid are mixed in 0.365 moles of water. Determine the following: [CH3COOH], [CH3COO^-], pH and pOH.
Ka=1.8E-5.
Calculate the pH of 0.05M CH3COO-Na+ .
Plz show me step by step, really confused right now.
2 answers
If I read this problem correctly it provides numbers that are entirely unrealistic and I don't want to tackle it. For example, 0.365 mol H2O = approx 6.6 grams. If the density is 1.0 g/mL that is about 0.0066 liters which makes the HCl about 0.250/0.0066 = approx 38 M and there is no such animal.
But these are the numbers which have been provided in the question...
If u could show me just the way to tackle it, it wud be very helpful,plz.
If u could show me just the way to tackle it, it wud be very helpful,plz.
1 answer