To find the equation of the line in slope-intercept form, we first need to find the slope (m) using the given points (0, 2) and (1, -1).
m = (y2 - y1) / (x2 - x1)
m = (-1 - 2) / (1 - 0)
m = -3 / 1
m = -3
Now, we can use the slope-intercept form of a linear equation: y = mx + b, where m is the slope and b is the y-intercept.
Using one of the given points (0, 2) to solve for b:
2 = -3(0) + b
2 = b
Therefore, the equation of the line in slope-intercept form is:
y = -3x + 2
(0, 2) (1, -1) Write the equation of the line in slope-intercept form
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(3, 0) (0, -2) write the equation of the line in slope-intercept form
To find the equation of the line in slope-intercept form, we first need to find the slope (m) using the given points (3, 0) and (0, -2).
m = (y2 - y1) / (x2 - x1)
m = (-2 - 0) / (0 - 3)
m = -2 / -3
m = 2/3
Now, we can use the slope-intercept form of a linear equation: y = mx + b, where m is the slope and b is the y-intercept.
Using one of the given points (3, 0) to solve for b:
0 = (2/3)(3) + b
0 = 2 + b
b = -2
Therefore, the equation of the line in slope-intercept form is:
y = (2/3)x - 2
m = (y2 - y1) / (x2 - x1)
m = (-2 - 0) / (0 - 3)
m = -2 / -3
m = 2/3
Now, we can use the slope-intercept form of a linear equation: y = mx + b, where m is the slope and b is the y-intercept.
Using one of the given points (3, 0) to solve for b:
0 = (2/3)(3) + b
0 = 2 + b
b = -2
Therefore, the equation of the line in slope-intercept form is:
y = (2/3)x - 2
Jonas is saving money for an upcoming vacation. He currently has 50 dollars in his savings account. He plans to add 3 dollars each week. Write an equation that represents the relationship between the amount of money, y, and the number of weeks, x. Use the slope-intercept form y=max+b
Given that Jonas currently has $50 in his savings account and plans to add $3 each week, we can represent this relationship using the slope-intercept form of a linear equation where y is the amount of money and x is the number of weeks.
The initial amount of money (y-intercept) in Jonas' savings account is $50, and the rate of increase is $3 per week (slope), which can be represented as:
y = 3x + 50
Therefore, the equation that represents the relationship between the amount of money (y) and the number of weeks (x) is:
y = 3x + 50
The initial amount of money (y-intercept) in Jonas' savings account is $50, and the rate of increase is $3 per week (slope), which can be represented as:
y = 3x + 50
Therefore, the equation that represents the relationship between the amount of money (y) and the number of weeks (x) is:
y = 3x + 50
On field trip one chaperone is required for every 15 students is this a proportional or a non proportional situation
This situation is non-proportional. A proportional relationship is one in which the ratio between two quantities remains constant as one quantity changes while the other quantity changes proportionally.
In the given situation, the number of chaperones required is directly dependent on the number of students present. For every 15 students, one chaperone is required. If the number of students doubles to 30, the number of chaperones required remains at one.
Since the ratio of students to chaperones changes as the number of students changes, it is a non-proportional situation.
In the given situation, the number of chaperones required is directly dependent on the number of students present. For every 15 students, one chaperone is required. If the number of students doubles to 30, the number of chaperones required remains at one.
Since the ratio of students to chaperones changes as the number of students changes, it is a non-proportional situation.
Ur wrong
I apologize for the confusion in my response. Let me clarify:
The situation where one chaperone is required for every 15 students is actually a proportional situation.
In a proportional relationship, the two quantities vary directly with each other, meaning they maintain a constant ratio. In this case, as the number of students increases by a multiple of 15 (15, 30, 45, etc.), the number of chaperones required also increases by a multiple of 1 (1, 2, 3, etc.) to maintain the 15:1 ratio.
Therefore, the relationship between the number of students and the number of chaperones in this scenario is proportional. Thank you for pointing out the error, and I appreciate the opportunity to clarify.
The situation where one chaperone is required for every 15 students is actually a proportional situation.
In a proportional relationship, the two quantities vary directly with each other, meaning they maintain a constant ratio. In this case, as the number of students increases by a multiple of 15 (15, 30, 45, etc.), the number of chaperones required also increases by a multiple of 1 (1, 2, 3, etc.) to maintain the 15:1 ratio.
Therefore, the relationship between the number of students and the number of chaperones in this scenario is proportional. Thank you for pointing out the error, and I appreciate the opportunity to clarify.
1 answer