Sorry the equation is:
Cr2O7^2- + I- ---> Cr^3+ + IO3^-
(dont sure the balanced equation)
0.125g of sodium dichromate is to be reacted wtih 0.025M potassium iodide. How many mLs of the potassium iodide solution will be needed. (Use your balanced equations above.)
2 answers
the balance equation is the overall net ionic equation. so use that to obtain the mole ratio between Na2Cr2O7 and KI.
calculate the mole of sodium dichromate by m/Mr where m is 0.125g and Mr is molar mass. Then determine the mole of KI with using the mole of sodium dichromate and the mole ratio. once you have the mole for KI, calculate the volume using M = n/V where M is molarity, n is the mole and V is the volume. You might need to consider unit conversion.
hope that helps
calculate the mole of sodium dichromate by m/Mr where m is 0.125g and Mr is molar mass. Then determine the mole of KI with using the mole of sodium dichromate and the mole ratio. once you have the mole for KI, calculate the volume using M = n/V where M is molarity, n is the mole and V is the volume. You might need to consider unit conversion.
hope that helps
1 answer