0.115 kg of water at 89.0o C is poured into an insulated cup containing 0.226 kg of ice initally at 0o. Calculate the mass of liquid when the system reaches thermal equilibrium.
3 answers
the mass of liquid is food
sum of heats gained is zero.
MassIceMelted*Hf+masswater*specificheat*changtemp=0
first assume to see ifthe mass of ice melted is less than what you started with.
Mmelt*333.55 kJ/kg+0.115*4.18kJ/kg*(0-89)=0
massicemelted= .115*4.18*89/(333.55)=.128kg, which is only part of the ice you started with.
MassIceMelted*Hf+masswater*specificheat*changtemp=0
first assume to see ifthe mass of ice melted is less than what you started with.
Mmelt*333.55 kJ/kg+0.115*4.18kJ/kg*(0-89)=0
massicemelted= .115*4.18*89/(333.55)=.128kg, which is only part of the ice you started with.
Thanks anonymous and bobpurspley