∫(0, 1)〖x(1-√x)^2 dx〗

Answer 1

∫[0,1] x(1-√x)^2 dx
= ∫ x(1-2√x+x) dx
= ∫ x - 2x^(3/2) + x^2 dx
= 1/2 x^2 - 4/5 x^(5/2) + 1/3 x^3 = (1/2 - 4/5 + 1/3) = 1/30