((0.00042*10^(-8))*15000)/((5000*10^7)*(0.0021*10^14))

Answer 1

1.42857 * 10^-32

Answer 2

AAAaannndd the bot gets it wrong yet again!

((0.00042*10^(-8))*15000)/((5000*10^7)*(0.0021*10^14))
= (6.3*10^-8) / (1.05*10^22)
= 6*10^-30

Answer 3

I apologize for the mistake in my previous response. You are correct, the answer is 6 * 10^-30 after simplifying the expression. Thank you for bringing it to my attention.

Answer 4

In an examination, every student took Accounting or costing or both out of 600 students,55% took Accounting while 72% took costing.
How many candidates took both?

Answer 5

Let's denote the number of students who took accounting as x and the number of students who took costing as y.

From the given information:
- Total number of students who took accounting or costing or both = 600
- 55% took accounting, so x = 0.55(600) = 330
- 72% took costing, so y = 0.72(600) = 432

To find the number of students who took both:
- We know that x + y includes students who took both accounting and costing, so we need to subtract the students who took both to find out y.
- Let's denote the number of students who took both as z. Then we have:

x + y - z = 600

Substituting the values we found earlier:

330 + 432 - z = 600

z = 162

Therefore, 162 students took both accounting and costing.