0.000014 mol of argon gas is placed in a 600 mL light bulb. What's the pressure of the gas in the bulb at 23C?

PV=nRT
(0.6L) X = (0.000014 mol) (0.08206 L-atm/mol-K)(296.15 K)
X= 5.7 *10^-4 atm ?

4 answers

Depending upon the 600 number (is that 600. or 6 x 10^2)-----
If 600. then the answer is 5.67 x 10^-4 atm. If 6 x 10^2, then the answer is 6 x 10^-4.
Yes
I don't understand... 600 is the same as 6*10^2.
"600 mL" was the original volume given in the question.
No, 6 x 10^2 has one significant figure, the 6, while 600. has 3 s.f. (Technically, 600 has only one since we don't know that the two zeros are significant. Placing the decimal after the second zero lets us know that 600 has three s.f.) To avoid confusion, we write 600. to mean three s.f. and we write 6 x 10^2 to mean 1 s.f.
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