Use the following formula to find the efficiency of energy transfer between the harbor seal (2,500 Kcal) and a polar bear (375 Kcal).

Question

(Energy level transfered to next level)(Total energy input) × 100


(1 point)
Responses

15%
15%

20%
20%

12%
12%

10%
10%

Answer 1

To find the efficiency of energy transfer between the harbor seal and the polar bear, we can use the given formula:

\[ \text{Efficiency} = \left(\frac{\text{Energy level transferred to next level}}{\text{Total energy input}}\right) \times 100 \]

In this case, the energy transferred to the polar bear (next level) is 375 Kcal (energy of the polar bear) and the total energy input is 2,500 Kcal (energy of the harbor seal).

Now, plug in the numbers:

\[ \text{Efficiency} = \left(\frac{375 \text{ Kcal}}{2500 \text{ Kcal}}\right) \times 100 \]

Calculating the fraction:

\[ \frac{375}{2500} = 0.15 \]

Now multiply by 100 to get the efficiency percentage:

\[ 0.15 \times 100 = 15% \]

So, the efficiency of energy transfer between the harbor seal and polar bear is 15%.