To determine the maximum number of games Kelly can play, we first account for the admission cost and then the cost of the games.
- Total Money Kelly has: $10
- Admission Cost: $3
- Cost per Game: $0.25
After paying for admission, the amount remaining for games is: \[ 10 - 3 = 7 \]
Let \( x \) represent the number of games Kelly can play. The total cost of playing \( x \) games is \( 0.25x \). So, we set up the inequality based on the money left after admission: \[ 0.25x \leq 7 \]
This can also be expressed as: \[ 0.25x + 3 \leq 10 \]
Thus, the correct answer for the inequality that can be used to determine the maximum number of games Kelly can play is: 0.25x + 3 ≤ 10
Question 2
Now we solve for \( x \) to find the maximum number of games:
Starting from the inequality: \[ 0.25x + 3 \leq 10 \] Subtract 3 from both sides: \[ 0.25x \leq 7 \] Now, divide both sides by 0.25: \[ x \leq \frac{7}{0.25} \] \[ x \leq 28 \]
So, Kelly can play at most 28 games.