Kelly is attending a fall carnival with only $10. Admission into the carnival is $3 and each game inside the carnival costs $0.25.

Which inequality can be used to determine the maximum number games Kelly can play?

(1 point)
Responses

0.25x+3≤10
0 point 2 5 x plus 3 is less than or equal to 10

0.25x+3≥10
0 point 2 5 x plus 3 is greater than or equal to 10

0.25x+3<10
0.25x+3<10

0.25x+3>10
0 point 2 5 x plus 3 is greater than 10
Question 2
(1 point)
Kelly has enough money to play at most
games

1 answer

To determine the maximum number of games Kelly can play, we first account for the admission cost and then the cost of the games.

  1. Total Money Kelly has: $10
  2. Admission Cost: $3
  3. Cost per Game: $0.25

After paying for admission, the amount remaining for games is: \[ 10 - 3 = 7 \]

Let \( x \) represent the number of games Kelly can play. The total cost of playing \( x \) games is \( 0.25x \). So, we set up the inequality based on the money left after admission: \[ 0.25x \leq 7 \]

This can also be expressed as: \[ 0.25x + 3 \leq 10 \]

Thus, the correct answer for the inequality that can be used to determine the maximum number of games Kelly can play is: 0.25x + 3 ≤ 10

Question 2

Now we solve for \( x \) to find the maximum number of games:

Starting from the inequality: \[ 0.25x + 3 \leq 10 \] Subtract 3 from both sides: \[ 0.25x \leq 7 \] Now, divide both sides by 0.25: \[ x \leq \frac{7}{0.25} \] \[ x \leq 28 \]

So, Kelly can play at most 28 games.