Question 1

Question

A school class is selling cookies for a fundraiser. The class has made 120 cookies to sell, and the supplies to make the cookies cost $22. The class wants to make at least $50 from selling cookies.

Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal?

(1 point)
Responses

120p−22≥50
120 p minus 22 is greater than or equal to 50

120p−22>50
120 p minus 22 is greater than 50

120p−22<50
120p−22<50

120p−22≤50
120 p minus 22 is less than or equal to 50
Question 2
(1 point)
The class should sell each cookie for
$0.60.

Answer 1

To determine the appropriate inequality for the situation described in Question 1, we start by identifying how to set up the problem.

The class has made 120 cookies and wants to make at least $50 from selling them after covering their costs.

1. Let \( p \) be the price per cookie.
2. The total revenue from selling 120 cookies would be \( 120p \).
3. The costs to make the cookies are $22.

To find the profit, we subtract the cost from the revenue:

\[ \text{Profit} = \text{Revenue} - \text{Cost} = 120p - 22 \]

The class wants to make at least $50, which gives us the inequality:

\[ 120p - 22 \geq 50 \]

So the correct response for Question 1 is:

120p - 22 ≥ 50

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For Question 2, if the class sells each cookie at $0.60, we can check if this price meets the goal.

1. Calculate total revenue with \( p = 0.60 \):

\[ \text{Total Revenue} = 120p = 120 \times 0.60 = 72 \]

2. Calculate profit:

\[ \text{Profit} = \text{Total Revenue} - \text{Cost} = 72 - 22 = 50 \]

Since the profit is exactly $50, selling each cookie for $0.60 meets the goal.

Therefore, the answer to "The class should sell each cookie for" is correct as stated: $0.60.

Answer 2

greater than
less than
at most
at least
exactly