To solve the equation \( 45x - 5 = \frac{1}{4} \), let's follow through the steps and fill in the missing numbers.
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Start with the original equation: \[ 45x - 5 = \frac{1}{4} \]
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You have transformed it into: \[ \frac{4}{5}x - 5 = \frac{1}{4} \] This transformation suggests dividing the entire equation by \( \frac{45}{5} = 9 \), so let's work with that first.
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Now, to isolate \( \frac{4}{5}x \), we need to add 5 to both sides: \[ \frac{4}{5}x = \frac{1}{4} + 5 \]
To add \( 5 \) (which can be expressed as \( \frac{20}{4} \)): \[ \frac{1}{4} + \frac{20}{4} = \frac{21}{4} \]
Thus, we have: \[ \frac{4}{5}x = \frac{21}{4} \]
- Next, we need to solve for \( x \). We divide both sides by \( \frac{4}{5} \): \[ x = \frac{\frac{21}{4}}{\frac{4}{5}} = \frac{21}{4} \cdot \frac{5}{4} = \frac{21 \times 5}{4 \times 4} = \frac{105}{16} \]
Hence, the completed equations are:
- \( \frac{4}{5}x = \frac{21}{4} \)
- \( x = \frac{105}{16} \)
To finalize your answers:
- \( 4/5x = \frac{21}{4} \)
- \( x = \frac{105}{16} \)