Write an equation in POINT SLOPE FORM of a line through point J(3,-2) with a slope of -5.(1 point)

1 answer

The point-slope form of a line is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

Given the point J(3, -2) and the slope -5, the equation in point-slope form is:

y - (-2) = -5(x - 3)

Simplifying the equation:

y + 2 = -5x + 15

Putting the equation in standard form by moving -5x to the left:

5x + y = 15 - 2

Simplifying further:

5x + y = 13

Therefore, the equation in point-slope form of a line through point J(3, -2) with a slope of -5 is y + 2 = -5(x - 3).